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COBOL example program that reads a sequential file and displays the records

Category > COBOL || Published on : Friday, May 8, 2015 || Views: 3640 || Sequential Files READ OPEN CLOSE File Description (FD) SELECT..ASSIGN COBOL Sample Program COBOL Example Program

      $ SET SOURCEFORMAT"FREE"
IDENTIFICATION DIVISION.
PROGRAM-ID.  SeqReadNo88.
AUTHOR.  Michael Coughlan.
* An example showing how to read a sequential file without
* using condition names.
* See SeqRead.CBL for the definitive example.


ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
    SELECT StudentFile ASSIGN TO "STUDENTS.DAT"
		ORGANIZATION IS LINE SEQUENTIAL.

DATA DIVISION.
FILE SECTION.
FD StudentFile.
01 StudentDetails.
   02  StudentId       PIC 9(7).
   02  StudentName.
       03 Surname      PIC X(8).
       03 Initials     PIC XX.
   02  DateOfBirth.
       03 YOBirth      PIC 9(4).
       03 MOBirth      PIC 9(2).
       03 DOBirth      PIC 9(2).
   02  CourseCode      PIC X(4).
   02  Gender          PIC X.

PROCEDURE DIVISION.
Begin.
   OPEN INPUT StudentFile
   READ StudentFile
      AT END MOVE HIGH-VALUES TO StudentDetails
   END-READ
   PERFORM UNTIL StudentDetails = HIGH-VALUES
      DISPLAY StudentId SPACE StudentName SPACE CourseCode SPACE YOBirth
      READ StudentFile
         AT END MOVE HIGH-VALUES TO StudentDetails
      END-READ
   END-PERFORM
   CLOSE StudentFile
   STOP RUN.

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